Check If a String Contains a Substring in Java
This article shows some useful ways on checking a string that contains a substring. I find this topic relevant to document as I may someday use this on another project. Also, other developers might look for an article online to help them solve their problem. Since this topic is very basic Java, I only added short description and sample code below.
//Create a string to evaluate
String phrase = "The big brown fox jumped over the lazy dog!";
//Check if it contains a case sensitive substring
boolean evaluation = phrase.contains("brown"); //returns true
evaluation = phrase.contains("Brown"); //returns false
evaluation = phrase.indexOf("fox jumped") > 0; //returns true
//Check if phrase starts with a substring
evaluation = phrase.startsWith("Th"); //returns true
//Check if phrase ends with a substring
evaluation = phrase.endsWith("og"); //returns true
//To check string with ignore case, we should be using regular expression
evaluation = string.matches("(?i).*i am.*"); //returns true
//Check if phrase starts with a substring
evaluation = string.matches("(?i)th.*"); //returns true
//Check if phrase ends with a substring
evaluation = string.matches("(?i).*adam"); //returns true
That is all for this article. I hope this helps you.
Paul Labis is a young software engineer who is passionate in programming. He is one of the co-founder of CDO-IT Group and an expert in web-based Java programming. He is a graduate of BS-Information Management in Ateneo de Cagayan-Xavier University and an experienced software engineer with focus on Java technologies.
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